(2x+5)^2-(2x-5)=0

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Solution for (2x+5)^2-(2x-5)=0 equation: 



(2x+5)^2-(2x-5)=0

We get rid of parentheses

(2x+5)^2-2x+5=0

We add all the numbers together, and all the variables

-2x+(2x+5)^2+5=0

We move all terms containing x to the left, all other terms to the right

-2x+(2x+5)^2=-5

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